2018x^2+x-2017=0

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Solution for 2018x^2+x-2017=0 equation:



2018x^2+x-2017=0
a = 2018; b = 1; c = -2017;
Δ = b2-4ac
Δ = 12-4·2018·(-2017)
Δ = 16281225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16281225}=4035$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-4035}{2*2018}=\frac{-4036}{4036} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+4035}{2*2018}=\frac{4034}{4036} =2017/2018 $

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